This can be amended by pulling the names into the current scope using using
:
template<typename T> struct Subclass : public Superclass<T> {
using Superclass<T>::b;
using Superclass<T>::g;
void f() {
g();
b =3;
}
};
Or by qualifying the name via the this
pointer access:
template<typename T> struct Subclass : public Superclass<T> {
void f() {
this->g();
this->b = 3;
}
};
Or, as you’ve already noticed, by qualifying the full name.
accessing protected members of superclass in C++ with templates